Mathematics

Mathematics

Problem

The temperature TT (in ∘C^{\circ}\mathrm C) of a cooling liquid is given by T=5c2+20T = 5c^{2}+20, where cc is its concentration in mol L−1^{-1}. At an instant when c=3c = 3 and the concentration is decreasing at 0.020.02 mol L−1^{-1} per minute, the rate of change of temperature is a) 0.6  ∘C / min0.6\;^{\circ}\mathrm C\,/\,\text{min} b) 30  ∘C / min30\;^{\circ}\mathrm C\,/\,\text{min} c) −0.2  ∘C / min-0.2\;^{\circ}\mathrm C\,/\,\text{min} d) −0.6  ∘C / min-0.6\;^{\circ}\mathrm C\,/\,\text{min}

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