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Mathematics
Mathematics
Problem
Solve the multiple–angle sine equation
sin
3
x
=
1
2
\sin 3x = \dfrac{1}{2}
sin
3
x
=
2
1
. a. (i) Obtain the general solution for
3
x
3x
3
x
that satisfies
sin
3
x
=
1
2
\sin 3x = \dfrac{1}{2}
sin
3
x
=
2
1
. b. (ii) Hence, derive the general solution for
x
x
x
. c. (iii) List all solutions of
x
x
x
that lie in the interval
[
0
,
2
π
)
[0,\,2\pi)
[
0
,
2
π
)
.
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