Principles of Quantum Mechanics · Problem 15.3.4

Addition of Angular Momenta — R. Shankar

Physics — Quantum Mechanics · magnetic-moment-two-angular-momenta

Problem

(1) Consider a system whose angular momentum consists of two parts J1\mathbf{J}_1 and J2\mathbf{J}_2 and whose magnetic moment is μ=γ1J1+γ2J2\boldsymbol{\mu} = \gamma_1 \mathbf{J}_1 + \gamma_2 \mathbf{J}_2 In a state ∣jm,j1j2⟩|jm, j_1 j_2\rangle show, using Eq. (15.3.19), that ⟨μx⟩=⟨μy⟩=0\langle\mu_x\rangle = \langle\mu_y\rangle = 0 ⟨μz⟩=mℏ[γ1+γ22+(γ1−γ2)2j1(j1+1)−j2(j2+1)j(j+1)]\langle\mu_z\rangle = m\hbar\left[\frac{\gamma_1 + \gamma_2}{2} + \frac{(\gamma_1 - \gamma_2)}{2}\frac{j_1(j_1+1) - j_2(j_2+1)}{j(j+1)}\right] (2) Apply this to the problem of a proton (g=5.6g = 5.6) in a 2P1/2^2P_{1/2} state and show that ⟨μz⟩=±0.26\langle\mu_z\rangle = \pm 0.26 nuclear magnetons. (3) For an electron in a 2P1/2^2P_{1/2} state show that ⟨μz⟩=±13\langle\mu_z\rangle = \pm\frac{1}{3} Bohr magnetons.

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