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Mathematics
Mathematics
Problem
In a triangle ABC, if
s
−
a
s-a
s
−
a
,
s
−
b
s-b
s
−
b
,
s
−
c
s-c
s
−
c
are in GP, then
sin
2
A
+
sin
2
C
sin
A
+
sin
C
=
\frac{\sin^2 A + \sin^2 C}{\sin A + \sin C} =
s
i
n
A
+
s
i
n
C
s
i
n
2
A
+
s
i
n
2
C
=
(a)
sin
B
\sin B
sin
B
(b)
cos
B
\cos B
cos
B
(c)
sin
[
(
A
+
C
)
/
2
]
\sin[(A+C)/2]
sin
[(
A
+
C
)
/2
]
(d)
sin
[
(
A
−
C
)
/
2
]
\sin[(A-C)/2]
sin
[(
A
−
C
)
/2
]
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