Introduction to Electrodynamics · Problem 3.37

Potentials — David J. Griffiths

Physics · laplace-equation-average-value

Problem

In Section 3.1.4, I proved that the electrostatic potential at any point PP in a charge-free region is equal to its average value over any spherical surface (radius RR) centered at PP. Here's an alternative argument that does not rely on Coulomb's law, only on Laplace's equation. We might as well set the origin at PP. Let Vave(R)V_{\text{ave}}(R) be the average; first show that dVavedR=14πR2∮∇V⋅da\frac{dV_{\text{ave}}}{dR} = \frac{1}{4\pi R^2}\oint \nabla V \cdot d\mathbf{a} (note that the R2R^2 in dad\mathbf{a} cancels the 1/R21/R^2 out front, so the only dependence on RR is in VV itself). Now use the divergence theorem, and conclude that if VV satisfies Laplace's equation, then Vave(R)=Vave(0)=V(P)V_{\text{ave}}(R) = V_{\text{ave}}(0) = V(P), for all RR.

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