Physics

Problem

Two oscillations are described by

y_1 = 3\sin(100\pi t)

and

y_2 = 3\sin(100\pi t + \dfrac{\pi}{2})

, where

t

is in seconds. The time by which the second oscillation lags behind the first is a)

\dfrac{1}{400}\,\text{s}

\dfrac{\pi}{200}\,\text{s}

\dfrac{1}{200}\,\text{s}

\dfrac{1}{100}\,\text{s}