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Mathematics
Problem
100
−
121
k
2
=
0
100-121k^2=0
100
−
121
k
2
=
0
What are the solutions to the equation above? A.
k
=
100
121
k=\frac{100}{121}
k
=
121
100
B.
k
=
−
100
121
k=-\frac{100}{121}
k
=
−
121
100
and
k
=
100
121
k=\frac{100}{121}
k
=
121
100
C.
k
=
10
11
k=\frac{10}{11}
k
=
11
10
D.
k
=
−
10
11
k=-\frac{10}{11}
k
=
−
11
10
and
k
=
10
11
k=\frac{10}{11}
k
=
11
10
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