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Problem
Problem
At a definite temperature, the equilibrium constant for a reaction,
A
+
B
⇌
2
C
A + B \rightleftharpoons 2C
A
+
B
⇌
2
C
, was found to be 81. Starting with 1 mole
A
A
A
and 1 mole of
B
B
B
, the mole fraction of
C
C
C
at equilibrium is : a.
9
11
\frac{9}{11}
11
9
b.
1
11
\frac{1}{11}
11
1
c.
2
11
\frac{2}{11}
11
2
d.
7
11
\frac{7}{11}
11
7
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