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Mathematics
Problem
Explain why
d
d
x
[
(
3
x
−
2
)
7
]
\dfrac{d}{dx}\bigl[(3x-2)^{7}\bigr]
d
x
d
[
(
3
x
−
2
)
7
]
equals
7
(
3
x
−
2
)
6
⋅
3
7(3x-2)^{6}\cdot 3
7
(
3
x
−
2
)
6
⋅
3
rather than simply
7
(
3
x
−
2
)
6
7(3x-2)^{6}
7
(
3
x
−
2
)
6
. Your explanation should refer to how the derivative accounts for the rate of change of the inner expression.
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