Mathematics

Problem

Given

x^{2}\tan y+y^{2}=5

, determine

\displaystyle\frac{dy}{dx}

. a)

\displaystyle\frac{-2x\tan y}{x^{2}\sec^{2}y}

\displaystyle\frac{-2x\tan y}{x^{2}\sec^{2}y+2y}

\displaystyle\frac{2x\tan y}{x^{2}\sec^{2}y+2y}

\displaystyle\frac{-2x\tan y}{x^{2}\sec y\tan y+2y}