Basic Analysis I — Real Analysis · Problem 1.2.14

Real Numbers — Jiri Lebl

Mathematics — Real Analysis · supremum-infimum

Problem

Prove sup⁡{x∈Q:x2<2}=sup⁡{x∈R:x2<2}\sup\{x \in \mathbb{Q} : x^2 < 2\} = \sup\{x \in \mathbb{R} : x^2 < 2\}.

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