Statement I f(x)={2−x,x<12−x2,x≥1, mean value theorem is applicable in the interval [0,1].\text{Statement I } f(x) = \begin{cases} 2 - x, & x < 1 \\ 2 - x^2, & x \ge 1 \end{cases} \text{, mean value theorem is applicable in the interval } [0, 1].…

Problem

Statement I f(x)={2−x,x<12−x2,x≥1, mean value theorem is applicable in the interval [0,1].\text{Statement I } f(x) = \begin{cases} 2 - x, & x < 1 \\ 2 - x^2, & x \ge 1 \end{cases} \text{, mean value theorem is applicable in the interval } [0, 1]. Statement II For application of mean value theorem, f(x)f(x) must be continuous in [0,1][0, 1] and differentiable in (0,1)(0, 1).

Browse the problem library