Problem

Problem

Let A=[aij]3×3A = [a_{ij}]_{3 \times 3} be such that aij={3;when i=j0;i≠ja_{ij} = \begin{cases} 3; & \text{when } i = j \\ 0; & i \neq j \end{cases} , then {det⁡(adj(adj A))5}\left\{ \frac{\det(\text{adj}(\text{adj } A))}{5} \right\} equals : (where {⋅}\{ \cdot \} denotes fractional part function) (a) 25\frac{2}{5} (b) 15\frac{1}{5} (c) 23\frac{2}{3} (d) 13\frac{1}{3}

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