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Mathematics
Mathematics
Problem
6. Find
∣
a
⃗
∣
|\vec{a}|
∣
a
∣
and
∣
b
⃗
∣
|\vec{b}|
∣
b
∣
, if
(
a
⃗
+
b
⃗
)
⋅
(
a
⃗
−
b
⃗
)
=
8
(\vec{a}+\vec{b}) \cdot(\vec{a}-\vec{b})=8
(
a
+
b
)
⋅
(
a
−
b
)
=
8
and
∣
a
⃗
∣
=
8
∣
b
⃗
∣
|\vec{a}|=8|\vec{b}|
∣
a
∣
=
8∣
b
∣
.
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