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Mathematics
Mathematics
Problem
If
A
+
B
+
C
=
180
∘
A + B + C = 180^\circ
A
+
B
+
C
=
18
0
∘
, then prove that
sin
2
A
+
sin
2
B
+
sin
2
C
=
4
sin
A
sin
B
sin
C
\sin 2A + \sin 2B + \sin 2C = 4 \sin A \sin B \sin C
sin
2
A
+
sin
2
B
+
sin
2
C
=
4
sin
A
sin
B
sin
C
.
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