Mathematics

Mathematics

Problem

For f(x)=∣x−3∣f(x)=|x-3| and g(x)=1x+1g(x)=\dfrac{1}{x+1}, determine (g∘f)(x)(g\circ f)(x). a) 1∣x−3∣−1\dfrac{1}{|x-3|}-1 b) ∣x−3∣∣x−3∣+1\dfrac{|x-3|}{|x-3|+1} c) 1∣x−3∣+1\dfrac{1}{|x-3|+1} d) ∣x−3∣+1|x-3|+1

Browse the problem library