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Mathematics
Problem
The differential equation
d
2
y
d
x
2
=
−
sin
y
\frac{d^2y}{dx^2} = -\sin y
d
x
2
d
2
y
=
−
sin
y
, with
y
=
π
2
y = \frac{\pi}{2}
y
=
2
π
,
d
y
d
x
=
0
\frac{dy}{dx} = 0
d
x
d
y
=
0
at
x
=
0
x = 0
x
=
0
. a.
a
Find the values of
d
2
y
d
x
2
\frac{d^2y}{dx^2}
d
x
2
d
2
y
,
d
3
y
d
x
3
\frac{d^3y}{dx^3}
d
x
3
d
3
y
and
d
4
y
d
x
4
\frac{d^4y}{dx^4}
d
x
4
d
4
y
at
x
=
0
x = 0
x
=
0
. b.
b
Hence find the Maclaurin series for
y
y
y
, up to and including the term in
x
4
x^4
x
4
.
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