Problem

Problem

If ef(x)=10+x10−xe^{f(x)}=\frac{10+x}{10-x}, x∈(−10,10)x\in(-10,10) and f(x)=kf(200x100+x2), then k=f(x)=k f\left(\frac{200x}{100+x^2}\right), \text{ then } k =

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