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Mathematics
Mathematics
Problem
Solve for
θ
\theta
θ
(
0
∘
<
θ
<
90
∘
0^\circ<\theta<90^\circ
0
∘
<
θ
<
9
0
∘
) if
sin
2
θ
=
cos
θ
\sin^2\theta = \cos\theta
sin
2
θ
=
cos
θ
. Give your answer to the nearest degree. a)
45
∘
45^{\circ}
4
5
∘
b)
52
∘
52^{\circ}
5
2
∘
c)
38
∘
38^{\circ}
3
8
∘
d)
60
∘
60^{\circ}
6
0
∘
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