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Mathematics
Mathematics
Problem
Determine the absolute minimum value of
m
(
t
)
=
9
t
2
+
1
m(t)=\sqrt{9t^{2}+1}
m
(
t
)
=
9
t
2
+
1
on the closed interval
[
−
2
,
2
]
[-2,2]
[
−
2
,
2
]
.
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