Introduction to Electrodynamics · Problem 11.19

Electrodynamics and Relativity — David J. Griffiths

Physics · radiation-reaction

Problem

With the inclusion of the radiation reaction force (Eq. 11.80), Newton's second law for a charged particle becomes a=τa˙+Fm,a = \tau\dot{a} + \frac{F}{m}, where FF is the external force acting on the particle. (a) In contrast to the case of an uncharged particle (a=F/ma = F/m), acceleration (like position and velocity) must now be a continuous function of time, even if the force changes abruptly. (Physically, the radiation reaction damps out any rapid change in aa.) Prove that aa is continuous at any time tt, by integrating the equation of motion above from (t−ϵ)(t - \epsilon) to (t+ϵ)(t + \epsilon) and taking the limit ϵ→0\epsilon \to 0. (b) A particle is subjected to a constant force FF, beginning at time t=0t = 0 and lasting until time TT. Find the most general solution a(t)a(t) to the equation of motion in each of the three periods: (i) t<0t < 0; (ii) 0<t<T0 < t < T; (iii) t>Tt > T. (c) Impose the continuity condition (a) at t=0t = 0 and t=Tt = T. Show that you can either eliminate the runaway in region (iii) or avoid preacceleration in region (i), but not both. (d) If you choose to eliminate the runaway, what is the acceleration as a function of time, in each interval? How about the velocity? (The latter must, of course, be continuous at t=0t = 0 and t=Tt = T.) Assume the particle was originally at rest: v(−∞)=0v(-\infty) = 0. (e) Plot a(t)a(t) and v(t)v(t), both for an uncharged particle and for a (nonrunaway) charged particle, subject to this force.

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