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Mathematics
Problem
Prove that the lines
x
+
1
3
=
y
+
3
5
=
z
+
5
7
\frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}
3
x
+
1
=
5
y
+
3
=
7
z
+
5
and
x
−
2
1
=
y
−
4
4
=
z
−
6
7
\frac{x-2}{1} = \frac{y-4}{4} = \frac{z-6}{7}
1
x
−
2
=
4
y
−
4
=
7
z
−
6
are coplanar. Also, find the plane containing these two lines.
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