Chemistry

Chemistry

Problem

Calculate the temperature at which the decomposition of calcium carbonate becomes spontaneous. CaCO3(s)→CaO(s)+CO2(g)ΔH⊖=+178 kJ mol−1ΔS⊖=+164 J K−1 mol−1\text{CaCO}_3(\text{s}) \rightarrow \text{CaO}(\text{s}) + \text{CO}_2(\text{g}) \quad \Delta H^\ominus = +178 \text{ kJ mol}^{-1} \quad \Delta S^\ominus = +164 \text{ J K}^{-1} \text{ mol}^{-1}

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