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If
∣
6
−
3
1
4
3
−
1
20
3
1
∣
=
x
+
i
y
,
i
=
−
1
\begin{vmatrix} 6 & -3 & 1 \\ 4 & 3 & -1 \\ 20 & 3 & 1 \end{vmatrix} = x + iy, i = \sqrt{-1}
6
4
20
−
3
3
3
1
−
1
1
=
x
+
i
y
,
i
=
−
1
…
Mathematics
Problem
If
∣
6
−
3
1
4
3
−
1
20
3
1
∣
=
x
+
i
y
,
i
=
−
1
\begin{vmatrix} 6 & -3 & 1 \\ 4 & 3 & -1 \\ 20 & 3 & 1 \end{vmatrix} = x + iy, i = \sqrt{-1}
6
4
20
−
3
3
3
1
−
1
1
=
x
+
i
y
,
i
=
−
1
, then a.
x
=
3
,
y
=
1
x = 3, y = 1
x
=
3
,
y
=
1
b.
x
=
1
,
y
=
3
x = 1, y = 3
x
=
1
,
y
=
3
c.
x
=
0
,
y
=
3
x = 0, y = 3
x
=
0
,
y
=
3
d.
x
=
0
,
y
=
0
x = 0, y = 0
x
=
0
,
y
=
0
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