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Problem
Problem
A 1.0 kg bar of copper is heated at atmospheric pressure (
1.01
×
10
5
N/m
2
1.01 \times 10^5 \text{ N/m}^2
1.01
×
1
0
5
N/m
2
). If its temperature increases from
20
∘
C
20^\circ\text{C}
2
0
∘
C
to
50
∘
C
50^\circ\text{C}
5
0
∘
C
, calculate the change in its internal energy.
α
=
7.0
×
10
−
6
/
∘
C
\alpha = 7.0 \times 10^{-6} / ^\circ\text{C}
α
=
7.0
×
1
0
−
6
/
∘
C
,
ρ
=
8.92
×
10
3
kg/m
3
\rho = 8.92 \times 10^3 \text{ kg/m}^3
ρ
=
8.92
×
1
0
3
kg/m
3
and
c
=
387
J/kg
⋅
∘
C
c = 387 \text{ J/kg}\cdot^\circ\text{C}
c
=
387
J/kg
⋅
∘
C
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