Problem

Problem

A 1.0 kg bar of copper is heated at atmospheric pressure ( 1.01×105 N/m21.01 \times 10^5 \text{ N/m}^2 ). If its temperature increases from 20∘C20^\circ\text{C} to 50∘C50^\circ\text{C} , calculate the change in its internal energy. α=7.0×10−6/∘C\alpha = 7.0 \times 10^{-6} / ^\circ\text{C} , ρ=8.92×103 kg/m3\rho = 8.92 \times 10^3 \text{ kg/m}^3 and c=387 J/kg⋅∘Cc = 387 \text{ J/kg}\cdot^\circ\text{C}

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