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Mathematics
Mathematics
Problem
If
a
+
b
=
3
−
cos
4
θ
a + b = 3 - \cos 4\theta
a
+
b
=
3
−
cos
4
θ
and
a
−
b
=
4
sin
2
θ
a - b = 4 \sin 2\theta
a
−
b
=
4
sin
2
θ
, then
a
b
ab
ab
is always less than or equal to .....
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