Physics

Problem

The position of a projectile launched from the origin at

t=0

is given by

\vec{r} = (40\hat{i} + 50\hat{j})

m at

t=2

s. If the projectile was launched at an angle

\theta

from the horizontal, then

\theta

is (take

g = 10 \text{ ms}^{-2}

) (a)

\tan^{-1} \frac{2}{3}

(b)

\tan^{-1} \frac{3}{2}

(c)

\tan^{-1} \frac{7}{4}

(d)

\tan^{-1} \frac{4}{7}