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Mathematics
Mathematics
Problem
Let
p
(
t
)
=
q
(
k
(
t
)
)
p(t)=q\big(k(t)\big)
p
(
t
)
=
q
(
k
(
t
)
)
, where
q
(
v
)
=
⟨
v
,
v
2
,
1
v
⟩
q(v)=\left\langle\sqrt v,\,v^{2},\,\dfrac{1}{v}\right\rangle
q
(
v
)
=
⟨
v
,
v
2
,
v
1
⟩
and
k
(
t
)
=
sin
(
2
t
2
)
k(t)=\sin(2t^{2})
k
(
t
)
=
sin
(
2
t
2
)
. What is
p
′
(
π
4
)
p'\!\left(\sqrt{\dfrac{\pi}{4}}\right)
p
′
(
4
π
)
? a)
⟨
π
,
4
π
,
−
2
π
⟩
\left\langle\sqrt{\pi},\;4\sqrt{\pi},\;-2\sqrt{\pi}\right\rangle
⟨
π
,
4
π
,
−
2
π
⟩
b)
⟨
0
,
0
,
0
⟩
\langle 0,\,0,\,0\rangle
⟨
0
,
0
,
0
⟩
c)
⟨
1
2
,
2
,
−
1
⟩
\left\langle\dfrac12,\;2,\;-1\right\rangle
⟨
2
1
,
2
,
−
1
⟩
d)
⟨
0
,
0
,
−
2
π
⟩
\left\langle0,\;0,\;-\dfrac{2}{\sqrt{\pi}}\right\rangle
⟨
0
,
0
,
−
π
2
⟩
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