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If
a
=
49
g H
2
SO
4
+
(
3
×
10
23
molecule H
2
SO
4
)
−
(
0.02
N
H
2
SO
4
)
a = 49 \text{ g H}_2\text{SO}_4 + (3 \times 10^{23} \text{ molecule H}_2\text{SO}_4) - (0.02 N \text{H}_2\text{SO}_4)
a
=
49
g H
2
SO
4
+
(
3
×
1
0
23
molecule H
2
SO
4
)
−
(
0.02
N
H
2
SO
4
)
…
Chemistry
Problem
If
a
=
49
g H
2
SO
4
+
(
3
×
10
23
molecule H
2
SO
4
)
−
(
0.02
N
H
2
SO
4
)
a = 49 \text{ g H}_2\text{SO}_4 + (3 \times 10^{23} \text{ molecule H}_2\text{SO}_4) - (0.02 N \text{H}_2\text{SO}_4)
a
=
49
g H
2
SO
4
+
(
3
×
1
0
23
molecule H
2
SO
4
)
−
(
0.02
N
H
2
SO
4
)
, then the value of
a
a
a
is : a. 0.9 mol b. 0.99 mol c. 0.8 mol d. 0.88 mol
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