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Mathematics
Problem
For the curve
x
=
2
t
2
+
1
x=2t^{2}+1
x
=
2
t
2
+
1
and
y
=
3
t
−
4
y=3t-4
y
=
3
t
−
4
, find the slope
d
y
d
x
\dfrac{dy}{dx}
d
x
d
y
at
t
=
2
t=2
t
=
2
. a)
8
3
\dfrac{8}{3}
3
8
b)
3
8
\dfrac{3}{8}
8
3
c)
3
16
\dfrac{3}{16}
16
3
d)
3
4
\dfrac{3}{4}
4
3
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