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Chemistry
Problem The reaction 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( g ) 2\text{H}_2(g)+\text{O}_2(g)\rightarrow 2\text{H}_2\text{O}(g) 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( g ) has Δ H rxn ∘ = − 484 kJ \Delta H^\circ_{\text{rxn}}=-484\,\text{kJ} Δ H rxn ∘ = − 484 kJ . Given Δ H f ∘ ( H 2 ( g ) ) = 0 \Delta H_f^\circ\bigl(\text{H}_2(g)\bigr)=0 Δ H f ∘ ( H 2 ( g ) ) = 0 and Δ H f ∘ ( O 2 ( g ) ) = 0 \Delta H_f^\circ\bigl(\text{O}_2(g)\bigr)=0 Δ H f ∘ ( O 2 ( g ) ) = 0 , what is Δ H f ∘ \Delta H_f^\circ Δ H f ∘ for H 2 O ( g ) \text{H}_2\text{O}(g) H 2 O ( g ) ?
a) − 484 kJ mol − 1 -484\,\text{kJ mol}^{-1} − 484 kJ mol − 1
b) − 242 kJ mol − 1 -242\,\text{kJ mol}^{-1} − 242 kJ mol − 1
c) + 242 kJ mol − 1 +242\,\text{kJ mol}^{-1} + 242 kJ mol − 1
d) − 121 kJ mol − 1 -121\,\text{kJ mol}^{-1} − 121 kJ mol − 1
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