Mathematics

Problem

The mirror image of the curve

\arg\left(\frac{z-3}{z-i}\right) = \frac{\pi}{6}

i = \sqrt{-1}

in the real axis, is a.

\arg\left(\frac{z+3}{z+i}\right) = \frac{\pi}{6}

\arg\left(\frac{z-3}{z+i}\right) = \frac{\pi}{6}

\arg\left(\frac{z+i}{z+3}\right) = \frac{\pi}{6}

\arg\left(\frac{z+i}{z-3}\right) = \frac{\pi}{6}