Mathematics

Mathematics

Problem

∫e−2xsin⁡3x dx=\int e^{-2x} \sin 3x \, dx = (a) 113e−2x[sin⁡3x+cos⁡3x]+c\frac{1}{13} e^{-2x} [\sin 3x + \cos 3x] + c (b) −113e−2x[sin⁡3x+cos⁡3x]+c-\frac{1}{13} e^{-2x} [\sin 3x + \cos 3x] + c (c) 113e−2x[2sin⁡3x+3cos⁡3x]+c\frac{1}{13} e^{-2x} [2 \sin 3x + 3 \cos 3x] + c (d) −113e−2x[2sin⁡3x+3cos⁡3x]+c-\frac{1}{13} e^{-2x} [2 \sin 3x + 3 \cos 3x] + c (a) 113e−2x[sin⁡3x+cos⁡3x]+c\frac{1}{13} e^{-2x} [\sin 3x + \cos 3x] + c (b) −113e−2x[sin⁡3x+cos⁡3x]+c-\frac{1}{13} e^{-2x} [\sin 3x + \cos 3x] + c (c) 113e−2x[2sin⁡3x+3cos⁡3x]+c\frac{1}{13} e^{-2x} [2 \sin 3x + 3 \cos 3x] + c (d) −113e−2x[2sin⁡3x+3cos⁡3x]+c-\frac{1}{13} e^{-2x} [2 \sin 3x + 3 \cos 3x] + c

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