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Chemistry
Chemistry
Problem
Consider the following standard free-energy changes: Reaction I: X
→
\rightarrow
→
Y
Δ
G
∘
=
+
15.0
kJ
mol
−
1
\Delta G^{\circ}=+15.0\,\text{kJ}\,\text{mol}^{-1}
Δ
G
∘
=
+
15.0
kJ
mol
−
1
Reaction II: Y
→
\rightarrow
→
Z
Δ
G
∘
=
−
32.0
kJ
mol
−
1
\Delta G^{\circ}=-32.0\,\text{kJ}\,\text{mol}^{-1}
Δ
G
∘
=
−
32.0
kJ
mol
−
1
What is
Δ
G
∘
\Delta G^{\circ}
Δ
G
∘
for the overall conversion X
→
\rightarrow
→
Z? a)
+
17.0
kJ
mol
−
1
+17.0\,\text{kJ}\,\text{mol}^{-1}
+
17.0
kJ
mol
−
1
b)
−
17.0
kJ
mol
−
1
-17.0\,\text{kJ}\,\text{mol}^{-1}
−
17.0
kJ
mol
−
1
c)
−
47.0
kJ
mol
−
1
-47.0\,\text{kJ}\,\text{mol}^{-1}
−
47.0
kJ
mol
−
1
d)
−
32.0
kJ
mol
−
1
-32.0\,\text{kJ}\,\text{mol}^{-1}
−
32.0
kJ
mol
−
1
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