If Sn=(1−tan⁡4π23)(1−tan⁡4π24)…(1−tan⁡4π2n).S_n = \left(1 - \tan^4 \frac{\pi}{2^3}\right) \left(1 - \tan^4 \frac{\pi}{2^4}\right) \dots \left(1 - \tan^4 \frac{\pi}{2^n}\right).…

Problem

If Sn=(1−tan⁡4π23)(1−tan⁡4π24)…(1−tan⁡4π2n).S_n = \left(1 - \tan^4 \frac{\pi}{2^3}\right) \left(1 - \tan^4 \frac{\pi}{2^4}\right) \dots \left(1 - \tan^4 \frac{\pi}{2^n}\right). The value of lim⁡n→∞Sn\lim_{n\to\infty} S_n , is a. π34\frac{\pi^3}{4} b. 1 c. 2 d. 3

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