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Pt(s) ∣ H 2 ( g ) ( 1 bar ) ∣ H + ( aq ) ( 1 M ) ∣ ∣ M 3 + ( aq ) , M + ( aq ) ∣ Pt(s) \text{Pt(s)}|\text{H}_2(\text{g})(1\text{ bar})|\text{H}^+(\text{aq})(1\text{ M})||\text{M}^{3+}(\text{aq}),\text{M}^+(\text{aq})|\text{Pt(s)} Pt(s) ∣ H 2 ( g ) ( 1 bar ) ∣ H + ( aq ) ( 1 M ) ∣∣ M 3 + ( aq ) , M + ( aq ) ∣ Pt(s) …
Chemistry
Problem Pt(s) ∣ H 2 ( g ) ( 1 bar ) ∣ H + ( aq ) ( 1 M ) ∣ ∣ M 3 + ( aq ) , M + ( aq ) ∣ Pt(s) \text{Pt(s)}|\text{H}_2(\text{g})(1\text{ bar})|\text{H}^+(\text{aq})(1\text{ M})||\text{M}^{3+}(\text{aq}),\text{M}^+(\text{aq})|\text{Pt(s)} Pt(s) ∣ H 2 ( g ) ( 1 bar ) ∣ H + ( aq ) ( 1 M ) ∣∣ M 3 + ( aq ) , M + ( aq ) ∣ Pt(s)
The E cell E_{\text{cell}} E cell for the given cell is 0.1115 V at 298 K when [ M + ( aq ) ] [ M 3 + ( aq ) ] = 10 a \frac{[\text{M}^+(\text{aq})]}{[\text{M}^{3+}(\text{aq})]} = 10^a [ M 3 + ( aq )] [ M + ( aq )] = 1 0 a . The value of a a a is ____.
Given: E M 3 + / M + ∘ = 0.2 V E_{\text{M}^{3+}/\text{M}^+}^{\circ} = 0.2\text{ V} E M 3 + / M + ∘ = 0.2 V ; 2.303 R T F = 0.059 V \frac{2.303RT}{F} = 0.059\text{ V} F 2.303 R T = 0.059 V
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