Self-concordance and the inverse barrier.
((a)) Show that f(x)=1/x with domain (0,8/9) is self-concordant.
((b)) Show that the function
f(x)=αi=1∑mbi−aiTx1
with domf={x∈Rn∣aiTx<bi,i=1,…,m}, is self-concordant if domf is bounded and
α>(9/8)i=1,…,mmaxx∈domfsup(bi−aiTx).