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Problem
Problem
A triangle
A
B
C
ABC
A
B
C
is such that
sin
(
2
A
+
B
)
=
1
2
\sin(2A + B) = \frac{1}{2}
sin
(
2
A
+
B
)
=
2
1
. If
A
A
A
,
B
B
B
,
C
C
C
are in A.P., then find the value of
A
A
A
,
B
B
B
and
C
C
C
.
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