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Problem
Problem
Solve the equation
log
2
(
3
−
x
)
−
log
2
(
sin
3
π
4
5
−
x
)
=
1
2
+
log
2
(
x
+
7
)
.
\log_2(3-x) - \log_2 \left( \frac{\sin \frac{3\pi}{4}}{5-x} \right) = \frac{1}{2} + \log_2(x+7).
lo
g
2
(
3
−
x
)
−
lo
g
2
(
5
−
x
sin
4
3
π
)
=
2
1
+
lo
g
2
(
x
+
7
)
.
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