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JEE Advanced 2013 Paper 1 Mathematics Q11
Mathematics
Problem
Let
S
n
=
∑
k
=
1
4
n
(
−
1
)
k
(
k
+
1
)
/
2
k
2
\displaystyle S_n=\sum_{k=1}^{4n}(-1)^{k(k+1)/2}k^2
S
n
=
k
=
1
∑
4
n
(
−
1
)
k
(
k
+
1
)
/2
k
2
. Then
S
n
S_n
S
n
can take value(s)
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