Mathematics

Mathematics

Problem

If tan⁡−1y=tan⁡−1x+tan⁡−1(2x1−x2)\tan^{-1} y = \tan^{-1} x + \tan^{-1} \left( \frac{2x}{1-x^2} \right) , where ∣x∣<13|x| < \frac{1}{\sqrt{3}} . Then, the value of yy is [2015 JEE Main] a. 3x−x31−3x2\frac{3x-x^3}{1-3x^2} b. 3x+x31−3x2\frac{3x+x^3}{1-3x^2} c. 3x−x31+3x2\frac{3x-x^3}{1+3x^2} d. 3x+x31+3x2\frac{3x+x^3}{1+3x^2}

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