(1) Using ⟨jj∣J1∣aj⟩=[j/(j+1)]1/2 show that
⟨aj∣∣J1∣∣a′j′⟩=δaa′δjj′ℏ[j(j+1)]1/2
(2) Using J⋅A=JzAz+21(J−A++J+A−) (where A±=Ax±iAy) argue that
⟨a′jm′∣J⋅A∣ajm⟩=c⟨a′j∣∣A∣∣aj⟩
where c is a constant independent of a, a′ and A. Show that c=ℏ[j(j+1)]1/2δm,m′.
(3) Using the above, show that
⟨a′jm′∣Aq∣ajm⟩=ℏ2j(j+1)⟨a′jm∣J⋅A∣ajm⟩⟨jm′∣Jq∣jm⟩(15.3.…)