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Mathematics
Mathematics
Problem
Explain why the value of
∫
0
2
π
∣
sin
x
∣
d
x
\displaystyle\int_{0}^{2\pi}|\sin x|\,dx
∫
0
2
π
∣
sin
x
∣
d
x
equals the total area enclosed by the graph of
y
=
sin
x
y=\sin x
y
=
sin
x
and the
x
x
x
-axis on the interval
0
≤
x
≤
2
π
0\le x\le 2\pi
0
≤
x
≤
2
π
.
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