Mathematics

Problem

The value of the definite integral

\int_{\pi/8}^{3\pi/8} \frac{11 + 4 \cos 2x + \cos 4x}{1 - \cos 4x}\,dx

equals: (A)

-6 - \frac{\pi}{4}

(B)

6\sqrt{2} - \frac{\pi}{4}

(C)

12 - \frac{\pi}{2}

(D)

6 - \frac{\pi}{4}

(A)

-6 - \frac{\pi}{4}

(B)

6\sqrt{2} - \frac{\pi}{4}

(C)

12 - \frac{\pi}{2}

(D)

6 - \frac{\pi}{4}