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Mathematics
Problem
If
∣
z
∣
=
2
|z| = 2
∣
z
∣
=
2
and locus of
5
z
−
1
5z - 1
5
z
−
1
is the circle having radius
a
a
a
and
z
1
2
+
z
2
2
−
2
z
1
z
2
cos
θ
=
0
z_1^2 + z_2^2 - 2z_1z_2 \cos \theta = 0
z
1
2
+
z
2
2
−
2
z
1
z
2
cos
θ
=
0
, then
∣
z
1
∣
:
∣
z
2
∣
=
|z_1| : |z_2| =
∣
z
1
∣
:
∣
z
2
∣
=
1.
a
:
1
a : 1
a
:
1
2.
2
a
:
1
2a : 1
2
a
:
1
3.
a
:
10
a : 10
a
:
10
4. none of these
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