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Problem
Problem
Let
f
(
x
)
=
∫
0
x
cos
(
t
2
+
2
t
+
1
5
)
d
t
f(x) = \int_{0}^{x} \cos\left(\frac{t^2 + 2t + 1}{5}\right) dt
f
(
x
)
=
∫
0
x
cos
(
5
t
2
+
2
t
+
1
)
d
t
,
0
<
x
<
2
0 < x < 2
0
<
x
<
2
, then a. increases monotonically b. decreasing monotonically c. has one point of local maximum d. has one point of local minima
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