A van starts from rest and its velocity changes according to the following schedule:
• From t=0 to t=4s, the velocity increases uniformly from 0 to 20ms−1.
• From t=4s to t=8s, the velocity remains constant.
• From t=8s to t=12s, the velocity decreases uniformly from 20ms−1 to 4ms−1.
a. (i) Sketch a velocity–time graph that represents the above motion.
b. (ii) Calculate the instantaneous acceleration at t=3s, t=6s, and t=10s.
c. (iii) For which time interval(s) is the acceleration zero? Give a physical interpretation of this result.