Chemistry

Chemistry

Problem

The forward activation energy for a reaction is 120 kJ mol−1120\,\text{kJ mol}^{-1}, and the overall enthalpy change is ΔH=−35 kJ mol−1\Delta H = -35\,\text{kJ mol}^{-1}. What is the activation energy for the reverse reaction? a) 85 kJ mol−185\,\text{kJ mol}^{-1} b) 155 kJ mol−1155\,\text{kJ mol}^{-1} c) 120 kJ mol−1120\,\text{kJ mol}^{-1} d) 35 kJ mol−135\,\text{kJ mol}^{-1}

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