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Problem
Problem
In a triangle
A
B
C
ABC
A
B
C
, medians
A
D
AD
A
D
and
C
E
CE
C
E
are drawn. If
A
D
=
5
AD = 5
A
D
=
5
,
∠
D
A
C
=
π
8
\angle DAC = \frac{\pi}{8}
∠
D
A
C
=
8
π
and
∠
A
C
E
=
π
4
\angle ACE = \frac{\pi}{4}
∠
A
C
E
=
4
π
, then the area of the triangle
A
B
C
ABC
A
B
C
is equal to
5
a
b
\frac{5a}{b}
b
5
a
, then
a
+
b
a+b
a
+
b
is equal to .....
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