Physics

Physics

Problem

For a particle executing simple harmonic motion, the phase changes by Δϕ\Delta \phi radians in a small time interval Δt\Delta t. Which one of the following expressions gives Δt\Delta t in terms of Δϕ\Delta \phi and the angular frequency ω\omega? a) Δt=2π Δϕω\displaystyle \Delta t = \dfrac{2\pi\,\Delta \phi}{\omega} b) Δt=Δϕω\displaystyle \Delta t = \dfrac{\Delta \phi}{\omega} c) Δt=sin⁡(Δϕ)ω\displaystyle \Delta t = \dfrac{\sin(\Delta \phi)}{\omega} d) Δt=Δϕ2π ω\displaystyle \Delta t = \dfrac{\Delta \phi}{2\pi\,\omega}

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